#spline-interpolation #spline #interpolation #geometry #numbers

no-std pythagorean-hodographs

Pythaogrean hodograph splines

11 releases

0.5.4 Dec 9, 2023
0.5.3 Dec 31, 2022
0.4.0 Dec 27, 2022
0.3.3 Dec 27, 2022
0.1.0 Dec 10, 2022

#462 in Math

MIT/Apache

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pythagorean-hodographs

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Implementations of Pythagorean hodograph (PH) splines in Rust, based on the work of R. Farouki and this paper by Zbyněk Šír & Bert Jüttler.

What are Pythagorean hodographs?

Pythaogrean hodographs are interpolating polynomial curves that satisfy an analogue of the Pythagorean identity. To illustrate, let $\mathbf{p}(t)$ be a polynomial parametric curve in $\mathbb{R}^2$. If there exist polynomials $u(t), v(t), w(t)$ such that the following holds:

$$\begin{equation} \frac{d\mathbf{p}(t)}{dt} = \begin{bmatrix} u(t)^2 - v(t)^2 \ 2u(t)v(t) \ \end{bmatrix}\cdot w(t) \end{equation}$$

then $\mathbf{p}(t)$ is a Pythaogrean hodograph, because $(u^2-v^2)^2+(2uv)^2=(u^2+v^2)^2,$ a perfect square of a polynomial. It then follows that $|\mathbf{p}'(t)|=(u(t)^2+v(t)^2)\cdot w(t).$ $\mathbf{p}(t)$ is then a planar PH curve.

There are many useful properties of Pythagorean hodographs as a result of this:

  1. The tangent vector, $\frac{\mathbf{p}'(t)}{|\mathbf{p}'(t)|},$ has rational functions as components. This makes computing the tangent fast, although square roots nowadays have dedicated CPU instructions.

  2. The arc-length function $s(t)=\int_0^t|\mathbf{p}'(\tau)|\ d\tau$ is a polynomial function.

  3. As a corollary of #2, computing the arc-length parameterization is trivial using Newton's method.

  4. In three dimensions, Pythagorean hodographs have a naturally associated moving frame called the Euler-Rodrigues frame.

Spatial PH curves

Well-studied readers may have noticed a connection to complex numbers. In particular, if $x(t)=u(t)+iv(t),$ then $p(t)=x(t)^2$ (where $\mathbf{p}(t)$ and $p(t)$ are equivalent via the map from $\mathbb{R}^2\rightarrow\mathbb{C}$).

Complex numbers are isomorphic to the plane, but we need something else if we want to model three dimensions -- quaternions. One has the following presentation: $\mathbf{r}(t)$ is a spatial PH curve if there exists a quaternionic polynomial curve $\mathcal{A}(t)$ such that

$$\begin{equation} \begin{gathered} \begin{aligned} \mathcal{A}(t)&=u(t)+v(t)\cdot\mathbf{i}+p(t)\cdot\mathbf{j}+q(t)\cdot\mathbf{k} \ r'(t)&=-\mathcal{A}(t)\ \mathbf{k}\ \bar{\mathcal{A}}(t)\ &=-2[u(t)p(t)+v(t)q(t)]\cdot\mathbf{i}+2[u(t)v(t)-p(t)q(t)]\cdot\mathbf{j}+2[u(t)^2-v(t)^2-p(t)^2+q(t)^2]\cdot\mathbf{k} \end{aligned} \end{gathered} \end{equation}$$

It then holds that $|\mathbf{r}'(t)|=|\mathcal{A}(t)|^2.$

The Euler-Rodrigues frame

With spatial PH curves, there is a naturally associated moving frame called the Euler-Rodrigues frame. One has the following formula for the tangent, normal, and binormal:

$$\begin{equation} \begin{bmatrix} \mathbf{T}(t) \ \mathbf{N}(t) \ \mathbf{B}(t) \end{bmatrix} = \begin{bmatrix} \mathcal{A}(t)\ \mathbf{i}\ \bar{\mathcal{A}}(t)\ \mathcal{A}(t)\ \mathbf{j}\ \bar{\mathcal{A}}(t) \ \mathcal{A}(t)\ \mathbf{k}\ \bar{\mathcal{A}}(t) \end{bmatrix} \end{equation}$$

or, more succinctly, the rotation matrix $[\mathbf{T\ N\ B}]$ is equivalent to the 3-dimensional rotation associated with the quaternion $\mathcal{A}(t).$

Dependencies

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~120K SLoC