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0.1.0 | Apr 3, 2019 |
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#1070 in Algorithms
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Used in 173 crates
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longest-increasing-subsequence
Longest Increasing Subsequence
The longest increasing subsequence problem is to find a subsequence of a given sequence in which the subsequence's elements are in sorted order, lowest to highest, and in which the subsequence is as long as possible. This subsequence is not necessarily contiguous, or unique.
For example, consider this sequence of integers:
2, 9, 4, 7, 3, 4, 5
The longest increasing subsequence (LIS) for this sequence is 2, 3, 4, 5.
Note that there is not always a singular LIS. Consider this sequence:
2, 6, 5
In this sequence, both 2, 5 and 2, 6 are LISs.
API
This crate exposes two functions for finding a longest increasing subsequence within a slice:
-
The high-level, easy-to-use
lis
function takes any slice ofT: Ord
and returns the LIS as a vector of indices into that slice. -
The low-level
lis_with
function takes a custom comparator and lets you bring your own allocations (which lets you choose to reuse allocations or use a custom allocator).
Both functions use the same underlying algorithm. They execute in O(n log n) time and use O(n) memory.
Example
use longest_increasing_subsequence::lis;
let xs = vec![9, 2, 8, 3, 5];
for i in lis(&xs) {
println!("{} at index {}", xs[i], i);
}
// Prints:
// 2 at index 1
// 3 at index 3
// 5 at index 4