43 releases (21 breaking)
new 0.22.2 | Jan 10, 2025 |
---|---|
0.22.0 | Dec 20, 2024 |
0.21.0 | Nov 14, 2024 |
0.15.2 | Jul 12, 2024 |
#369 in Data structures
333 downloads per month
220KB
4.5K
SLoC
matreex
A simple matrix implementation.
Quick Start
First, we need to import matrix!
.
use matreex::matrix;
Addition
let lhs = matrix![[0, 1, 2], [3, 4, 5]];
let rhs = matrix![[2, 2, 2], [2, 2, 2]];
assert_eq!(lhs + rhs, matrix![[2, 3, 4], [5, 6, 7]]);
Subtraction
let lhs = matrix![[0, 1, 2], [3, 4, 5]];
let rhs = matrix![[2, 2, 2], [2, 2, 2]];
assert_eq!(lhs - rhs, matrix![[-2, -1, 0], [1, 2, 3]]);
Multiplication
let lhs = matrix![[0, 1, 2], [3, 4, 5]];
let rhs = matrix![[0, 1], [2, 3], [4, 5]];
assert_eq!(lhs * rhs, matrix![[10, 13], [28, 40]]);
Division
let lhs = matrix![[0.0, 1.0, 2.0], [3.0, 4.0, 5.0]];
let rhs = matrix![[2.0, 2.0, 2.0], [2.0, 2.0, 2.0]];
assert_eq!(lhs / rhs, matrix![[0.0, 0.5, 1.0], [1.5, 2.0, 2.5]]);
Wait, matrix division isn't well-defined, remember? It won't compile. But don't worry, you might just need to perform elementwise division:
let lhs = matrix![[0.0, 1.0, 2.0], [3.0, 4.0, 5.0]];
let rhs = matrix![[2.0, 2.0, 2.0], [2.0, 2.0, 2.0]];
assert_eq!(lhs.elementwise_div(&rhs), Ok(matrix![[0.0, 0.5, 1.0], [1.5, 2.0, 2.5]]));
Or scalar division:
let matrix = matrix![[0.0, 1.0, 2.0], [3.0, 4.0, 5.0]];
assert_eq!(matrix / 2.0, matrix![[0.0, 0.5, 1.0], [1.5, 2.0, 2.5]]);
let matrix = matrix![[1.0, 2.0, 4.0], [8.0, 16.0, 32.0]];
assert_eq!(2.0 / matrix, matrix![[2.0, 1.0, 0.5], [0.25, 0.125, 0.0625]]);
Or maybe the inverse of a matrix?
Nah, we don't have that yet.
FAQs
Why named matreex
?
Hmm ... Who knows? Could be a name conflict.
Dependencies
~1.5MB
~26K SLoC