df1t-cyph

Just a stupid rust based encryption algorithm made without following the cryptography standards. the name literally stands for tf is this cypher!

Note: this project is made for experimenting purposes and it's highly discouraged to consider it as a serious encryption solution

How this thing works?

Like every other encrytion algorithm, it takes a string and a 16 char max salt as an arguments.

this is the beta version of df1t-cyph which has some limitaions:

• the accuracy isn't tested yet which mean you may get inconsistant results.
• the df1t-encrypt accepts only the alphabetical upper and lower case letters and fixed numbers only.

Encryption

the df1t-encrypt function goes through 6 stages to generate the final result:

• input parsing
• first level mapping
• mixing and switching
• mathematical transformation
• data swapping second level mapping
• result arrangement

input parsing

in this stage, the function will try to parse the passed arguments into a consistant vectors with the same lengths.

arg extending

First, both arguments lengths will get compared and the shortest will get extended by itself until it fulfills the longer argument length.

E.g. let's take "superpassword" as a password and "somesalt" as a salt. obviously the salt is shorter by 5 chars. after extending it, it should look like this : "somesaltsomes".

if both args are equal in length this step get skipped.

vec transformation

simply, both args will get splitted into vectors

First level mapping

here the function will run an iteration process on an internal lib that has arrays which represents each char with its mapped equivalent and returns it in a new vector.

the same thing will be applied on the salt vector but with diffrent equivalent char to gain a unique mapping.

Mixing and switching

After getting the mapped version of both salt and password which somehow should look like this:

a switching function will take both as args and mixed them based on the following criteria:

• if the first chars of the elements salt and password wasn't equal, the salt char will be taken.
• if the second chars of the elements wasn't equal, the password char will be taken.
• if both chars was equal, flip them
• if two chars was equal the second couple wasn't ignore them.

here's the visual explanation:

Mathematical transformation

numerical transformation

in this level, the mixed vector elements will get splitted to get a single char element vector e.g.

["d","S","n","U","n","P","E","E"]

thus, another iteration will run over the previous lib to get the equivalent mx_as number.

the iteration results should look like this:

[145, 654, 879, 147, 963, 123, 412]

matrixial representaion

here, the function turns the vector into a n*n matrix. First, it calculates the n of the matrix by finding the sqrt of the last vector then checks if n x n actually equals the vector length, if not then it adds 1 to n.

following this path leads to get extra empty elements since it only have 28 elements to fulfill a 36 matrix. thus, the empty elements will get filled by 101

vectorial transformation

the matrix get splitted by three main vectors following this representaion:

after that, the matrix length will get added to each element of the three vectors

Data swapping (second level mapping)

while we used a fixed ref in the first mapping level, now we gonna make it a bit dynamic with the use of ceaser substitution over a set of ~ 70 diffrent chars as a refrence.

the ceaser swapping goes as follows:

• move to right by the green vector length + 2 for the green vector
• move to right by the red vector length for the red vector
• move to right by the blue vector length + red vector length + 1 for the blue vector

finally, each vector will get joined to a string.

Result arrangement

The function will concatenate the results in one single string. the original length of the password + green vec + red vec + blue vec

• the original length of the password go through the same process of ceaser swapping with moving by 142. however,the length will be needed for the decryption stage.

for concatination, the function will add $ between each elements to make it parsable for the decrytion.